Solid lead(11) carbonate reacts with a dilute solution of nitric acid (HNO,) to give a solution of lead(II) nitrate,
carbon dioxide and water.

PbCO₃ + 2HNO₃ –> Pb(NO₃)₂ + CO₂ + H₂O

Explanation:

From the question given above:

Solid lead (II) carbonate reacts with a dilute solution of nitric acid (HNO₃) to give a solution of lead (II) nitrate,

carbon dioxide and water.

The above can be represented in the equation form as follow:

PbCO₃ + HNO₃ –> Pb(NO₃)₂ + CO₂ + H₂O

Finally, we shall balance the equation as follow:

PbCO₃ + HNO₃ –> Pb(NO₃)₂ + CO₂ + H₂O

There are 2 atoms of H on the right side and 1 atom on the left side. It can be balance by putting 2 in front of HNO₃ as shown below:

PbCO₃ + 2HNO₃ –> Pb(NO₃)₂ + CO₂ + H₂O

Now, the equation is balanced.