A flask containing a volume of 180 L of bromine was collected under a pressure of 35.5 kPa. What pressure would have been required for the volume of the gas to have been 80.0 L, assuming the same temperature? Which gas law did you need to use?

P₂ = 80 KPa

Boyle's law is applied.

Explanation:

Given data:

Initial volume = 180 L

Initial pressure = 35.5 KPa

Final pressure = ?

Final volume = 80.0 L

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

35.5 KPa × 180 L = P₂ × 80.0 L

P₂ = 6390 KPa. L/ 80.0 L

P₂ = 80 KPa

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

the transfer of heat by electromagnetic radiation is called thermal radiation . it is usually carried out by electromagnetic waves in an energy range just below the visible spectrum, which is the infrared range.

so the answer would be radiation.

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