In the free radical chlorination of methylcyclopentane, what is the total number of distinct monochlorinated compounds, including stereoisomers, that would be formed? A) 4
B) 6
C) 8
D) 10

B) 6

Explanation:

Methylcyclopentane consist of 3 types of hydrogen which are 1° (primary), 2° (secondary) and 3° (tertiary) hydrogen atoms. In the chlorination of methylcyclopentane, there are four monochlorinated products possible and two stereoisomers.

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6