Chemistry, 21.12.2020 17:50 krishawnnn
A voltaic cell is constructed that is based on the following reaction:
Sn2+(aq)+Pb(s)→Sn(s)+Pb2+(aq).
If the concentration of Sn2+ in the cathode compartment is 1.00 M and the cell generates an emf of 0.16 V , what is the concentration of Pb2+ in the anode compartment?
Answers: 2
are standard reduction potentials.![E^0_{[Sn^{2+}/Sn]}=-0.14V](/tpl/images/1004/1474/81a51.png)
![E^0_{[Pb^{2+}/Pb]}=-0.13V](/tpl/images/1004/1474/82211.png)
![E^0=E^0_{[Sn^{2+}/Sn]}- E^0_{[Pb^{2+}/Pb]}](/tpl/images/1004/1474/cb409.png)
![E=E^0-\frac{0.059}{n}\log\frac{[Pb^{2+}]}{[Sn^{2+}]}](/tpl/images/1004/1474/ec777.png)
![0.16=(-0.01)-\frac{0.059}{2}\log\frac{[Pb^{2+}]}{[1.00]}](/tpl/images/1004/1474/70ccb.png)
![0.17=-0.0295\log\frac{[Pb^{2+}]}{[1.00]}](/tpl/images/1004/1474/5042d.png)
![-5.76=\log\frac{[Pb^{2+}]}{[1.00]}](/tpl/images/1004/1474/a4415.png)
![1.74\times 10^{-6}=\frac{[Pb^{2+}]}{[1.00]}](/tpl/images/1004/1474/3d2ba.png)
![[Pb^{2+}]=1.74\times 10^{-6}](/tpl/images/1004/1474/109b6.png)
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A voltaic cell is constructed that is based on the following reaction:
Sn2+(aq)+Pb(s)→Sn(s)+Pb2+(a...
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