A sample of an unknown compound is vaporized at 150.°C . The gas produced has a volume of 960.mL at a pressure of 1.00atm , and it weighs 0.941g . Assuming the gas behaves as an ideal gas under these conditions, calculate the molar mass of the compound. Round your answer to 3 significant digits.

the  molar mass of the compound is  34.0 g /mol

Explanation:

The computation of the molar mass of the compound is as follows:

As we know that

PV = nRT

n = mass ÷ MW

PV = mRT ÷ MW

It can be rearrange as

MW = mRT ÷ (PV)

MW = (0.941)(0.082)(150 + 273) ÷ (1 × 0.96)

= 33.99g/mol

= 34.0 g /mol

Hence, the  molar mass of the compound is  34.0 g /mol

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.