Please answer for me.

54.5%

Explanation:

The percentage composition of oxygen in C₆H₈O₆ can be obtained as follow:

Molar mass of C₆H₈O₆ = (12×6) + (8×1) + (16×6)

= 72 + 8 + 96

= 176 g/mol

Next, there are 6 oxygen atoms in C₆H₈O₆. Therefore the mass of oxygen in C₆H₈O₆ is:

Mass of Oxygen = 16 × 6 = 96 g

Finally, we shall determine the percentage composition of oxygen in C₆H₈O₆ as follow:

Percentage of oxygen =

Mass of Oxygen/mass of C₆H₈O₆ × 100

Percentage of oxygen = 96 / 176 × 100

Percentage of oxygen = 54.5%

Thus, the percentage composition of oxygen in C₆H₈O₆ is 54.5%.

the dependant variable is spilled water

the independent is the heat