The reaction of magnesium chloride with silver nitrate gives a precipitate of silver chloride. MgCl2(aq) + 2AgNO3(aq) + Mg(NO3)2(aq) + 2AgCl(s)
A solution containing 0.001 mol of magnesium chloride reacts with excess silver nitrate.
What is the mass of the precipitate formed?
[Molar mass/gmol-': AgCl = 143.4]
A 0.0729
B 0.1439
C 0.287g
D 0.574g
(Total for Question 5 = 1 mark)

Mass = 0.287 g

Explanation:

Given data:

Number of moles of MgCl₂ = 0.001 mol

Mass of precipitate formed (AgCl) = ?

Solution:

Chemical equation:

MgCl₂(aq) + 2AgNO₃(aq)    →       Mg(NO₃)₂(aq) + 2AgCl (s)

now we will compare the moles of MgCl₂ and AgCl.

            MgCl₂           :            AgCl

                1                :             2

           0.001             :       2/1×0.001 = 0.002

Mass of AgCl:

Mass = number of moles × molar mass

Mass = 0.002 mol × 143.4 g/mol

Mass = 0.287 g

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

let that person have a turn to speak : )