In the equation FeCl3+ O2 -->Fe2O3 +Cl2
if 6 moles of FeCl3 react with 3 moles of oxygen, what is the excess reactant?

FeCl₃ is present in excess.

Explanation:

Given data:

Number of moles of FeCl₃ = 6 mol

Number of moles of oxygen = 3 mol

Excess reactant = ?

Solution:

Chemical equation:

4FeCl₃ + 3O₂      →    2Fe₂O₃ + 6Cl₂

Now we will compare the moles of reactant with product.

               FeCl₃         :          Fe₂O₃

                  4             :              2

                  6             :            2/4×6= 3

              FeCl₃         :              Cl₂

                  4             :               6

                  6             :            6/4×6= 9

                  O₂           :          Fe₂O₃

                  3             :              2

                  O₂          :              Cl₂

                   3             :               6

Less number of moles of product are formed by the oxygen thus it will act as limiting reactant while FeCl₃ is present in excess.

where are the choice options?