You have 165.5 g of Ba(OH)2. How many moles of barium ions are present in part 1?
mol Ba2+
How many moles of hydroxide ions are present in Part 1?
mol OH1-

moles of Ba²⁺ : 0.97 mol

Moles of OH⁻ : 1.94 mol

Explanation:

Given data:

Mass of Ba(OH)₂ = 165.5 g

Moles of barium ions = ?

Moles of hydroxide ion = ?

Solution:

Number of moles of barium hydroxide:

Number of moles = mass/molar mass

Number of moles = 165.5 g/ 171.34 g/mol

Number of moles = 0.97 mol

one mole of barium hydroxide contain one mole of Ba²⁺ and 2 mole of OH⁻ ion.

Thus in 0.97 moles of barium hydroxide,

moles of Ba²⁺ :

0.97 mol × 1 = 0.97 mol

Moles of OH⁻ :

0.97 mol × 2=  1.94 mol

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