Show, in a step by step fashion, your calculations to determine the percent by volume of a solution that is made by mixing 50 ml of ethanol with 210
ml of water.

The percent  by volume of a solution : 19.23%

Given

50 ml of ethanol

210  ml of water

Required

The percent  by volume of a solution

Solution

Percent Volume (% v/v) : volume (ml) of solute/100 ml of solution ⇒ ratio of the volume of the solute to total volume of the solution

solute= Ethanol

solvent=water

Solution = solute+solvent

Total volume of the solution :

Percent by volume :

1 a

2 d

3 a

4 c

explanation:

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2