A mixture of methane and oxygen gases at a total pressure of 727 mm Hg contains methane at a partial pressure of 571 mm Hg. If the gas mixture contains 3.62 grams of methane, how many grams of oxygen are present

1.95 g of oxygen is present.

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

Given : =total pressure of gases = 727 mm Hg

= partial pressure of methane = 571 mm Hg

= partial pressure of oxygen = ?

Also

Given : 3.62 g of methane is present

moles of methane =

= mole fraction of oxygen  

=

mass of oxygen =

Thus 1.95 g of oxygen is present.

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