3. The equation for the decomposition of sodium hydrogencarbonate is : 2 NaHCO3 (s) → Na2CO3 (s) + H2O(l) + CO2(8)
If 21 g of sodium hydrogencarbonate were decomposed, calculate
(a) the mass of the residue formed.
(b) the volume of carbon dioxide evolved measured at r. t.p.

a. 13.25 g

b. 3 L

Given

21 g of Sodium hydrogencarbonate

Reaction

2 NaHCO3 (s) → Na2CO3 (s) + H2O(l) + CO2(g)

Required

mass of residue

volume of CO2

Solution

mol  NaHCO₃ (MW=84 g/mol) :

a. the residue = Na₂CO₃

From the equation, mol ratio NaHCO₃ : Na₂CO₃ = 2 : 1, so mol Na₂CO₃ :

mass Na₂CO₃ (MW=106 g/mol) :

b. From equation, mol CO₂ = 0.5 x mol NaHCO₃ = 0.125

RTP= 25 C, 1 atm ⇒ 1 mol =24 L

So volume CO₂ :

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

if you need further assistance, let me know: )

~ trueboss72