The molar heat capacity is represented in the temp range 298 to 400 k by the emprical expression 14.73+0.1272 calculate the enthalpy if formation of ethane at 350 k from its valu at 298 k

Explanation:

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In this case, since the enthalpy of formation of ethane at 298 K is about -84 kJ/mol, via the Kirkoff's law, we can compute it a 350 K as shown below:

It means we can integrate to get:

Now, we can plug in the enthalpy of formation in consistent units to obtain:

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explanation:

the answer for sodium is 0.186

the answer for rubidium is 0.251