2.1. The lithium ion in a 250,00 mL sample of mineral water was precipitated with sodium tetraphenylboron:
Lit + B(C6H4)4 — LiB(CH3)4(s)
The precipitate was filtered, washed and re-dissolved in an organic
solvent. An excess of mercury (II) EDTA chelate was added:
4HgY2- + B(C6H4)4 + 4H20 =H3BO3 + 4C6H5Hg+ + 4HY3- + OH
The liberated EDTA was titrated with 29,64 mL of 0,05581 M Mg2+.
Calculate the lithium ion concentration in ppt.

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

→

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

i think is conclusions.i think so