The bottle of hydrogen peroxide you used in Experiment 1: Ideal Gas Law - Finding Percent H2O2 is labeled as a 3% solution (the same as store-bought hydrogen peroxide). Do your experimental results support this (with consideration given to experimental error)

0.33%

Explanation:

So, from the question it is given that the mass of the hydrogen peroxide in percentage is = 3% that is to say there are 3.0grams of hydrogen peroxide in 100mL of water. Therefore, the number of moles of hydrogen peroxide = 3/ molar mass = 3/ 34.02 = 0.088 moles.

Also, the mass of hydrogen peroxide = number of moles × molar mass = 0.088 × 34.02 = 2.99grams. Hence, the percentage by mass = [2.99/100 mL 0f water] × 100 = 2.99%

Therefore, the error in percentage = [ (3 - 2.99)/3 ]% × 100 = 0.33%

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