A sample of water is heated from 10 °C to 50 °C using 286 J of energy. What is the mass of water that was heated? help

Mass of water == 1.71 g

Explanation:

Given data:

Initial temperature of water = 10°C

Final temperature of water = 50°C

Energy absorbed = 286 J

Mass of water = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water is 4.18 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  50°C -  10°C

ΔT = 40°C

by putting  values,

286 J = m × 4.18 J/g.°C × 40°C

286 J = m × 167.2 J/g

m = 286 J / 167.2 J/g

m = 1.71 g

b..

is the correct one

explanation:

covalent bonds form as valence electrons are shared between two atoms. lewis structures and structural formulas are common ways of showing the covalent bonding in organic molecules. formal charge describes the changes in the number of valence electrons as an atom becomes bonded into a molecule.