A solution is prepared by dissolving 250 g of CH4N2O into 6.0 L of solution. What is the molarity of this solution? M

Molarity = 0.65 M

Explanation:

Given data:

Mass of CH₄N₂O  = 250 g

Volume of solution = 6.0 L

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of solute:

Number of moles = mass/molar mass

Number of moles = 250 g/ 64.08 g/mol

Number of moles = 3.9 mol

by putting values,

Molarity = 3.9 mol / 6.0 L

Molarity = 0.65 M

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