If an archaebacterial species lives in a pool that is 0.01 M HCl(aq), what is the pH of the water

2

Explanation:

From the question given above, the following data were obtained:

Molarity of HCl = 0.01 M

pH =?

Next, we shall determine the concentration of the hydrogen ion, [H⁺] in the pool. This can be obtained as follow:

HCl (aq) <=> H⁺ (aq) + Cl¯ (aq)

From the balanced equation above,

1 mole of HCl produced 1 mole of H⁺.

Therefore, 0.01 M HCl will also produce 0.01 M H⁺.

Thus, the concentration of the hydrogen ion, [H⁺] in the pool is 0.01 M

Finally, we shall determine the pH of the pool.

This can be obtained as follow:

Concentration of the hydrogen ion [H⁺] = 0.01 M

pH J?

pH = – Log [H⁺]

pH = – Log 0.01

pH = 2

Therefore, the pH of the pool is 2.

m=9

step-by-step explanation:

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