In a lab, a student calculates the density of a piece of silver to be 8.74 g/cm3. The actual density of silver is 10.49 g/cm3. What was the student's percent error? Round your answer to 1 decimal place and be sure to include units

16.7%

Explanation:

From the question given above, the following data were obtained:

Measured density = 8.74 g/cm³

Actual density = 10.49 g/cm³

Percentage error =?

The percentage error of the student can be obtained by using the following formula:

Percentage error = | measured – Actual | / Actual × 100

Percentage error = | 8.74 – 10.49 |/10.49 × 100

Percentage error = 1.75 / 10.49 × 100

Percentage error = 16.7%

Therefore, the percentage error of the student is 16.7%

i think the answer is terrae but not 100 percent sure. ▓▬▬ §