Question 4 (1 point) 60.5 mL of 0.223 M HI is mixed with 86.0 mL of a buffer system composed of 0.385 M sodium acetate and 0.410 M acetic acid. Find the pH of

the final solution

Ko of acetic acid = 1.8 E-5

4561

o a

Ob

Ос

Od

4.673

4.450

4.349

pH = 4.349

Explanation:

When HI is added to sodium acetate, CH3COONa, acetic acid is produced as follows:

CH3COONa + HI → CH3COOH + NaI

That means the moles of HI added are the moles of acetic acid produced and the moles of sodium acetate consumed.

Moles of HI:

0.0605L * (0.223mol/L) = 0.01349mol

To find pH of the buffer (Mixture of weak acid, acetic acid, and conjugate base, sodium acetate) we need to solve H-H euation:

pH = pKa + log [CH3COONa] / [CH3COOH]

Where pKa is -log of Ka of the acid: -log1.8x10⁻⁵ = 4.745

And [] could be taken as moles of each specie

Moles CH3COONa:

Inital moles: 0.086L * (0.385mol/L) = 0.03311

Final moles: 0.03311mol - 0.01349mol = 0.01962mol CH3COONa

Moles CH3COOH:

Inital moles: 0.086L * (0.410mol/L) = 0.03256

Final moles: 0.03256mol + 0.01349mol = 0.04875mol CH3COOH

pH = 4.745+ log [0.01962mol CH3COONa] / [0.04875mol CH3COOH]

pH = 4.3497

Rigth answer is:

a corroding iron, if that's one of your choices

the term hydride is commonly named after binary compounds that hydrogen forms with other elements of the periodic table. hydride compounds in general form with almost any element, except a few noble gases. the trends and properties vary according to the type of intermolecular force that bonds the elements together, the temperature, its molecular masses, and other components. hydrides are classified into three major groups, depending on what elements the hydrogen bonds to. the three major groups are covalent, ionic, and metallic hydrides. formally, hydride is known as the negative ion of a hydrogen, h-, also called a hydride ion. because of this negative charge, hydrides have reducing, or basic properties. its special characteristics will be further discussed.

explanation: