![[KOH]=\dfrac{10^{-2}}{10}\\\Rightarrow [KOH]=10^{-3}\ \text{M}](/tpl/images/1015/6356/4641b.png)
![[KOH]](/tpl/images/1015/6356/7ef8a.png)
is strong base so we have the following relation![[KOH]=[OH^{-}]=10^{-3}\ \text{M}](/tpl/images/1015/6356/3b7d0.png)
![pOH=-\log [OH^{-}]=-\log10^{-3}](/tpl/images/1015/6356/43cef.png)
2055 Q. No. 10^-2
mole of KOH is dissolved in 10 litres of
water. What will be the pH of the s...
Chemistry, 06.01.2021 04:40 hernan99961
2055 Q. No. 10^-2
mole of KOH is dissolved in 10 litres of
water. What will be the pH of the solution?
12
Ans: pH = 11
Answers: 2
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