If the rate constant of a reaction is 0.010 L/mols at 30 °C, calculate the rate constant at 100 °C assuming the rate doubles for each 10 °C rise in temperature. It says that the answer is 1.3 L/mols, but I don't understand why.

1.3L/mols

Explanation:

At 30°C the rate constant is 0.010L/mols

As the rate doubles for each 10° rise in temperature:

At 40°:

0.010L/mols*2 = 0.020L/mols

At 50°C:

0.020L/mols*2 = 0.040L/mols

At 60°C:

0.040L/mols*2 = 0.080L/mols

At 70°C:

0.080L/mols*2 = 0.160L/mols

At 80°C:

0.160L/mols*2 = 0.320L/mols

At 90°C:

0.320L/mols*2 = 0.640L/mols

And at 100°C:

0.640L/mols*2 =

1.280L/mols ≅

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explanation:

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.