In the process of underwater welding, a gas bubble is intentionally formed around the weld to protect it from water until it has cooled. To do so, a mixture of gas is used containing mole fractions of χH2=0.70 (70% hydrogen), χCO2=0.25 (25% carbon dioxide), and χCO=0.05 (5% carbon monoxide). If the total pressure on this gas bubble is 2.6 atm, what are the partial pressures of the three component gases (in atm)?

See explanation

Explanation:

Total number of moles of gases in the mixture; 0.70 + 0.25 + 0.05 = 1 mole

Partial pressure= mole fraction of gas × total pressure

Mole fraction of hydrogen = 0.7/1 × 2.6 = 1.82 atm

Mole fraction of CO2 = 0.25/1 × 2.6 = 0.65 atm

Mole fraction of CO= 0.05/1 × 2.6 = 0.13 atm

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

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