50g nitrous oxide combines with 50g oxygen form dinitrogen tetroxide according to the balanced equation below. 2N20 + 302 - 2N204

Limiting reactant : O₂

Mass of  N₂O₄ produced = 95.83 g

Given

50g nitrous oxide

50g oxygen

Reaction

2N20 + 302 - 2N204

Required

Limiting reactant

mass of N204 produced

Solution

mol N₂O :

mol O₂ :

2N₂O+3O₂⇒ 2N₂O₄

ICE method

1.136    1.5625

1.0416  1.5625    1.0416

0.0944    0          1.0416

Limiting reactant : Oxygen-O₂

Mass N₂O₄(MW=92 g/mol) :

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .

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