Curicun, named for marie curie, has approximately 25 different isotopes that emit an alpha particle when their nuclei decay. if curium-247, the most abundant nuclide, emit and alpha particle, what daughter nuclide is formed? A. Californium-251
B. Plutonium-243
C. Californium-249
D. Plutonium-251

Option B. Plutonium-243

Explanation:

To know the the correct answer to the question, we shall write the balanced equation for the reaction showing curium-247 (²⁴⁷Cm) emitting alpha particle. This is illustrated below:

²⁴⁷₉₆Cm —> ᵐₙX + ⁴₂He

Next, we shall determine m, n and X. This can be obtained as follow:

247 = m + 4

Collect like terms

247 – 4 = m

243 = m

Thus, m is 243

96 = n + 2

Collect like terms

96 – 2 = n

94 = n

Thus, n is 94

m = 243

n = 94

ᵐₙX => ²⁴³₉₄X => ²⁴³₉₄Pu

Thus, the equation is:

²⁴⁷₉₆Cm —> ²⁴³₉₄Pu + ⁴₂He

From the illustrations above, the daughter nuclei formed is Plutonium-243 (²⁴³₉₄Pu)

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.

the increase of protons   hope this