How many oxygen atoms are in 163 g of aluminum sulfate? 

3.44 × 10²⁴ atoms of oxygen

Explanation:

Step 1: Calculate the moles corresponding to 163 g of Al₂(SO₄)₃

The molar mass of Al₂(SO₄)₃ is 342.15 g/mol.

163 g × 1 mol/342.15 g = 0.476 mol

Step 2: Calculate the molecules in 0.476 moles of Al₂(SO₄)₃

We will use Avogadro's number: there are 6.02 × 10²³ molecules of Al₂(SO₄)₃ in 1 mole of Al₂(SO₄)₃.

0.476 mol × 6.02 × 10²³ molecules/1 mol = 2.87 × 10²³ molecules

Step 3: Calculate the atoms of O in 2.87 × 10²³ molecules of Al₂(SO₄)₃

According to the chemical equation, the molar ratio of Al₂(SO₄)₃ to O is 1:12. The atoms of O are 12/1 × 2.87 × 10²³ = 3.44 × 10²⁴.

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