How many calories of energy are required to heat an 87 g piece of iron from 30*C to 40*C?. ses

(The is the specific heat of iron is 0.110 cal/g x *C)

95.7 cal

Explanation:

The heat required can be calculated as follows:

heat = m x Cp x ΔT

Where:

m = mass of iron = 87 g

Cp = specific heat of iron = 0.110 cal/g.°C

ΔT = change in temperature = final T - initial T = 40°C - 30°C = 10°C

Thus, we introduce the data in the mathematical equation to calculate the heat in calories:

heat = 87 g x 0.110 cal/g.°C x 10°C = 95.7 cal

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

away from the curb

explanation:

the wheels would then hit the curb if it started to rolling, decreasing the chance of an accident.