How many moles of dinitrogen tetroxide (N2O4) are in 6.49 x 109 particles? 1.08 x 10–14 mol N2O4

3.091 x 1033 mol N2O4

6.02 x 1023 mol N2O4

1.08 x 10–23 mol N2O4

1.08 × 10⁻¹⁴ moles of N2O4

Explanation:

Given data:

Moles of dinitrogen tetroxide = ?

Number of particles = 6.49×10⁹

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions , particles and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole contain 6.022 × 10²³ particles.

6.49×10⁹ particles × 1 mole / 6.022 × 10²³ particles

1.08 × 10⁻¹⁴ mol

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.

bcde is the incorrect answer it is a