What is the mass of 5.2 x 10^21 atoms of Vanadium?

Mass = 0.44 g

Explanation:

Given data:

Mass of vanadium =  ?

Number of atoms of vanadium = 5.2 × 10²¹ atoms

Solution:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

5.2 × 10²¹ atoms ×  1mol / 6.022 × 10²³ atoms

0.86× 10⁻²  mol

0.0086 mol

Mass of vanadium:

Mass =  number of moles × molar mass

Mass = 0.0086 mol × 50.9 g/mol

Mass = 0.44 g

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.