Given: 36.7 grams of CaF2 is added to 300 mL water. Find molarity?

2 M

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Unit 0

Aqueous Solutions

Step 1: Define

36.7 g CaF₂

300 mL H₂O

Step 2: Identify Conversions

Molar Mass of Ca - 40.08 g/mol

Molar Mass of F - 19.00 g/mol

Molar Mass of CaF₂ - 40.08 + 2(19.00) = 78.08 g/mol

1000 mL = 1 L

Step 3: Convert

Solute

Solution

Step 4: Find Molarity

Step 5: Check

Follow sig fig rules and round. We are given 1 sig fig as our lowest.

1.56677 M ≈ 2 M

i'm not sure

explanation:

i'll try whatever you got

it is called acid bonding