An oxide of trivalent metal contains 32% of oxygen. Calculate the atomic mass of the metal.

The atomic mass of the metal.(M) = 51 g/mol

Given

32% of oxygen

Required

the atomic mass of the metal.

Solution

An oxide of trivalent metal : M₂O₃(Ar O = 16 g/mol)

The molar mass of metal oxide = 2M+16.3=2M+48

32% of oxygen, then :

32% x 2M+48 = 48

0.32(2M+48)=48

0.64M+15.36=48

0.64M=32.64

M=51

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