10. How many moles of Ne are in a 0.50L tube at 200kPa and 50 °C? 11,60

0.04 mol Ne

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Gas Laws

Combined Gas Law: PV = nRT

P is pressure (in kPa)V is volume (in liters)n is amount of molesR is gas constant - T is temperature (in Kelvins)

Explanation:

Step 1: Define

P = 200 kPa

V = 0.50 L

T = 50°C

Step 2: Identify Conversions

Temperature Conversion: K = °C + 273.15

Step 3: Convert

Substitute T [TC]:                      K = 50°C = 273.15Add:                                           K = 323.15

Step 4: Find Moles

Substitute [CBL]:                    Multiply:                                                                                                             Isolate n:                                                                                                          Rewrite:                                                                                                            

Step 5: Check

Follow sig fig rules and round. We are given 1 sig figs as our lowest.

0.037221 mol Ne ≈ 0.04 mol Ne