If the equilibrium constant for the reaction A 2B C 5/2 D has a value of 4.0, what is the value of the equilibrium constant for the reaction 2C 5D 2A 4B at the same temperature

Explanation:

Hello!

In this case, since the given reaction is:

Whereas the equilibrium constant is:

However, the new target reaction reverses and doubles the initial reaction to obtain:

Whereas the equilibrium constant is:

Which suggest the following relationship between the equilibrium constants:

So we plug in to obtain:

Best regards!

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

give me abc and i will get it for u.