1. in the reaction c5h8 + o2 --> 8h2o + 5co2, what coefficient should be placed in front of o2 to balance the reaction?

a. 5
b. 8
c. 9
d. no coefficient is needed

2. how does the law of conservation of mass apply to this reaction: c2h4 + o2 --> 2h2o + 2co2?

a. each element needs to be balanced.
b. the equation needs to be balanced. there are fewer oxygen atons in the equation than hydrogen or carbon.
c. only the oxygen needs to be balanced. there are equal numbers of hydrogen and carbon.
d. the law of conservation of mass has already been applied. there is an equal number of each element on both sides of the equation

3. how does the law of conservation of mass apply to this reaction: mg + hcl --> h2 + mgcl2?

a. the law of conservation of mass has already been applied. there is an equal number of each element on both sides of the equation.
b. only the hydrogen needs to be balanced. there are equal amount of magnesium and chlorine.
c. hydrogen and chlorine need to be balanced. there is an equal amount of magnesium on each side.
d. the equation needs to be balanced. there are a few hydrogen atoms in the equation than magnesium or chlorine.

4. which of these is an example of a solution?

a. oil and vinegar in a salad dressing jar
b. a glass of water with ice in it
c. sugar stirred in tea
d. sand stirred in water

For 1: The correct answer is Option c.

For 2: The correct answer is option c.

For 3: The correct answer is option c.

For 4: The correct answer is option c.

Explanation:

For 1:

For a given chemical reaction,

Number of oxygen atoms should be equal on both the sides of the reaction.

On reactant side:

Number of oxygen atoms = 2n

On product side:

Number of oxygen atoms = 18

As per the equation,

As, oxygen atoms should be same on both the sides, so 'n' should be equal to 9.

Hence, The correct option is Option c.

For 2:

Law of conservation of mass states that the total mass on the reactant side is equal to the total mass on the product side. This is achieved by balancing the number of atoms on both the sides.

For the given chemical equation:

On reactant side:

Number of carbon atoms = 2

Number of hydrogen atoms = 4

Number of oxygen atoms = 2n

On product side:

Number of carbon atoms = 2

Number of hydrogen atoms = 4

Number of oxygen atoms = 6

As, carbon and hydrogen atoms are equal on both the sides, so only oxygen atoms need to be balanced.

Hence, the correct answer is option c.

For 3:

Law of conservation of mass states that the total mass on the reactant side is equal to the total mass on the product side. This is achieved by balancing the number of atoms on both the sides.

For the given chemical equation:

On reactant side:

Number of Magnesium atoms = 1

Number of Hydrogen atoms = n

Number of Chlorine atoms = n

On product side:

Number of Magnesium atoms = 1

Number of Hydrogen atoms = 2

Number of Chlorine atoms = 2

As, Magnesium atoms are equal on both the sides, so Hydrogen and chlorine atoms need to be balanced.

Hence, the correct answer is option c.

For 4:

A solution consists of a solute( minor component) and a solvent(major component). These two substances are different compounds. A solution is formed when solute gets completely dissolved in solvent.

For the given options:

Option a: Oil and vinegar do not mix and hence, will not form a solution.

Option b: In this ice and water are two phases of same compound, that is So, this is not considered as a solution.

Option c: Sugar gets completely dissolved in tea. hence, it is a solution.

Option d: Sand and water do not mix and hence, not form a solution.

Therefore, the correct answer is option c.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2