Suppose you are performing a hydroboration oxidation of 1-hexene to form 1-hexanol. Your reaction includes 0.81 mL of 1-hexene, which has a density of 0.673 g/mL, 1.85 mL of 1.00 M borane in THF, and 1.22 mL of 30.0% m/v hydrogen peroxide. What is the theoretical yield of 1-hexanol (in g) for the reaction

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

the answer would be b i believe

explanation:

a