What mass of NaOH do you need to dissolve in 500ml of solution to obtain a 0.6mol / l solution?

Mass of NaOH required = 12 g

Given

500 ml solution = 0.5 L

Molarity = 0.6 mol / L

Required

mass of NaOH

Solution

Molarity = moles of solute per liter of solution

M = n / V

solute = NaOH

moles of solute = n  =  M x V

n = 0.6 x 0.5

n = 0.3 moles

Mass of NaOH = mol x MW

mass = 0.3 x 40 = 12 g

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

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