A robber is in a fast car, hurrying away from the scene of his crime. His car can go at 150 km/h. He will be safe if he can reach the border, 40km away. A police car arrives at the scene of the crime. The police are late! The robber has already travelled 10 km towards the border. The police car set off in hot pursuit. Question: calculate how long it will take the robber to reach the border. Question 2: How fast must the police car travel if it is to catch the robber before he reaches the border ?

If someone do I will make her or him brainliest.

1. time taken by the robber = 0.2 h

2. speed of the police's car = 200 km/h

Given

Speed of a robber's car = 150 km/h

Distance to border = 40 km

Required

1. time to reach border

2. speed of police's car

Solution

1. The robber has already travelled 10 km

Distance remains = 30 km

Time to reach = distance : speed = 30 km : 150 km/h = 0.2 h

2. time taken by robbers = time taken by police

distance needed by the police = 40 km

0.2 h = distance : speed

0.2 h = 40 km : speed

speed = 40 km : 0.2 = 200 km/h

that's just how they are

explanation:

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given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g