A 10.0 g piece of copper wire, sitting in the sun reaches a temperature of 80.0ºC. How many Joules are released when the copper cools to 40.0ºC? The specific heat capacity of copper is 0.377J/(g·ºC)

Q = -150.8 J

Explanation:

Given data:

Mass of copper = 10.0 g

Initial temperature = 80.0°C

Heat released = ?

Final temperature = 40.0 °C

Specific heat capacity of copper = 0.377J/(g·ºC)

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 40.0 °C - 80.0 °C

ΔT = -40.0 °C

by putting values,

Q = 10.0 g × 0.377J/g·ºC× -40.0 °C

Q = -150.8 J

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