What is the change in temperature if
2355 cal heats 51.5 g of water?

45.73°C

Explanation:

Given parameters:

Quantity of heat  = 2355cal

Mass of water  = 51.5g

Unknown:

Change in temperature  = ?

Solution:

To solve this problem, use the expression below;

      H  = m c Ф  

H is the quantity of heat

m is the mass

c is the specific heat of water  = 1cal/g°C

Ф is the change in temperature  = ?

Now insert the parameters and solve;

          H  = 51.5 x 1 x Ф  

      2355  = 51.5 x Ф

          Ф   = 45.73°C

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