Calculate the number of carbon hydrogen and oxygen atoms in 1.5 gram of glucose

The number of atoms :

C = 6 x 5 x 10²¹ = 3 x 10²²

H = 12 x 5 x 10²¹ = 6 x 10²²

O =  6 x 5 x 10²¹ = 3 x 10²²

Further explanation

Given

1.5 g glucose(C₆H₁₂O₆)

Required

The number of atoms

Solution

mol of glucose(MW=6.12+12.1+6.16=180 g/mol) :

mol = mass : MW

mol = 1.5 : 180

mol = 0.0083

Number of molecules = 0.0083 x 6.02 x 10²³ = 5 x 10²¹

There are 6 C, 12 H and 6 O, so number or atoms :

C = 6 x 5 x 10²¹ = 3 x 10²²

H = 12 x 5 x 10²¹ = 6 x 10²²

O =  6 x 5 x 10²¹ = 3 x 10²²

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

Hairy thick gross thing? idk