Hi, please I need help Reaction: C₄H₈S(I)+O₂(g)= CO₂(g)+H₂O(I)+SO₂(g)
5.95g of C₄H₈S is used. Calculate the masses of the products of the reacion.

The mass of ethanol (alcohol) = 538.016 g

Given

Reaction

C₁₂H₂₂O₁₁(aq)+H₂O(I) = CH₃CH₂OH(aq)+CO₂(g)

1 kg of sugar = 1000 g

Required

The mass of ethanol

Solution

Balanced equation

C₁₂H₂₂O₁₁(aq)+H₂O(I) = 4CH₃CH₂OH(aq)+4CO₂(g)

mol of sugar (MW = 12.12+22.1+11.16=342 g/mol) :

mol = mass : MW

mol = 1000 g : 342 g/mol

mol = 2.924

From the equation, mol ratio of C₁₂H₂₂O₁₁ : CH₃CH₂OH = 1 : 4, so mol ethanol =

= 4 x mol sugar

= 4 x 2.924

= 11.696

Mass of ethanol(MW=46 g/mol) :

mass = mol x MW

mass = 11.696 x 46

mass = 538.016 g

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)