Determine the Oxidation number of the indicated element in each of the following substances: Mn in KMnO4 S in SO2 C in COCl2 P in PF4 O in K2O2

1. Mn = +7

2. S = +4

3. C = +4

4. P = +4

5. O = -1

Explanation:

The oxidation number of each element in a compound is as follows:

1. Mn in KMnO4

KMnO4 = 0

Where; K = +1, O = -2, Mn = x

+1 + x -2(4) = 0

1 + x - 8 = 0

x - 7 = 0

x = +7

2. S in SO2

SO2 = 0

Where; S = x, O = -2

x + -2(2) = 0

x - 4 = 0

x = +4

3. C in COCl2

COCl2 = 0

Where; C = x, O = -2, Cl = -1

x + -2 + -1(2) = 0

x + -2 + -2 = 0

x -2 - 2 = 0

x - 4 = 0

x = +4

4. P in PF4

PF4 = 0

Where; P = x, F = -1

x + -1 (4) = 0

x - 4 = 0

x = +4

5. O in K2O2

K2O2 = 0

Where; K = +1, O = x

+1(2) + x(2) = 0

2 + 2x = 0

-2x = 2

x = -1

the answer is c.the valence of the atoms combine .