Determine the correct empirical formula of a compound containing 26.68% carbon, 2.24% hydrogen, and 71.08% oxygen.

The correct empirical formula of a compound containing 26.68% carbon, 2.24% hydrogen, and 71.08% oxygen is CHO₂

The empirical formulae shows us how elements in a compound are in their simplest ratio.

From the question, we can see  

Carbon (C) with  26.68%

Hydrogen (H)with  2.24%

Oxygen (O) with 71.08%

Now, the empirical formula of the compound can begotten following these steps:

Carbon  = 26.68 /12 = 2.223

Hydrogen= 2.24 / 1 = 2.24

Oxygen  = 71.08 / 16 = 4.4425

C arbon = 2.223 / 2.223 = 1

H ydrogen= 2.24 / 2.223 = 1

Oxygen  = 4.4425 /2.223 = 2

Giving us the empirical formula of the compound as CHO₂

See related question here:link

CHO₂

Explanation:

The following data were obtained from the question:

Carbon (C) = 26.68%

Hydrogen (H) = 2.24%

Oxygen (O) = 71.08%

Empirical formula =?

The empirical formula of the compound can be obtained as follow:

C = 26.68%

H = 2.24%

O = 71.08%

Divide by their molar mass.

C = 26.68 /12 = 2.223

H = 2.24 / 1 = 2.24

O = 71.08 / 16 = 4.4425

Divide by the smallest.

C = 2.223 / 2.223 = 1

H = 2.24 / 2.223 = 1

O = 4.4425 /2.223 = 2

Thus the empirical formula of the compound is CHO₂

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j