Balance this equation and pick the answer with the coefficients that belong there. A coefficient of 1 is understood but make the answers clear I will include the number 1.

Group of answer choices

2,3,6,1

2,3,6,1

3,1,2,1

3,2,1,6

4,6,6,2

2,3,6,1

2,3,6,1

Explanation:

The unbalanced reaction expression is given as:

  AlBr₃    +    K₂SO₄  →    KBr  + Al₂(SO₄)₃

We need to balanced this reaction equation. Our approach is a mathematical method where we assign variable a,b,c and d as the coefficients.

 aAlBr₃    +    bK₂SO₄  →    cKBr  + dAl₂(SO₄)₃

Conserving Al;  a  = 2d

                   Br:  3a  = c

                   K:   2b = c

                   S:   b  = 3d

                   O:  4b  = 12d

Let a  = 1, c = 3, d  =  b  =  

 Multiply through by 2 to give;

     a  = 2, b = 3, c = 6 and d  = 1

 2AlBr₃    +    3K₂SO₄  →    6KBr  + Al₂(SO₄)₃

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2