Calculate the percentage composition of Aluminum, Sulfur & Oxygen in the compound of Al(SO4)3

Percentage of O = 56.1 %

Percentage of Al =15.8%

Percentage of S = 28.1 %

Explanation:

Given compound Al₂(SO₄)₃

Molar mass of compound:

27×2 + 32×3 + 16×12 = 342 g/mol

Percentage of Al = ( Mass of Al / Total mass ) × 100

Percentage of Al = 54 /342 × 100

Percentage of Al =15.8%

Percentage of S = ( Mass of S / Total mass ) × 100

Percentage of S = 96 /342 × 100

Percentage of S = 28.1 %

Percentage of O = ( Mass of O / Total mass ) × 100

Percentage of O = 192 /342 × 100

Percentage of O = 56.1 %

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)