The combustion of acetylene gas is represented by the following chemical equation: 2C2H2(g) + 5O2(g) ---> 4CO2(g) + 2H20(g)

1. How many liters of CO2 are produced when 5.20 L of C2H2 burn in oxygen?

2. How many liters of oxygen are required to burn 3.50 L of acetylene?

P4O10 > 4P + 5O2

3. How many moles of phosphorus would be produced if 2.5 mol of P4O10 reacted?

4. How many grams of oxygen would be produced if 1.6 mol P4O10 reacted?

4 Al + 3O2 > 2Al2O3

5. How many moles of Al are needed to form 2.3 grams of Al2O3?