ASAP PLEASE I NEED TO BALANCE THEM PLZ HELP IM FAILING THANKS ILL GIVE BRAINLIEST

4H₂O(l) → 4H₂(g) + 2O₂(g)

Balancing equations

1. 3Fe(s) + 4H₂O(g) → Fe₃0₄(s) + 4H₂(g)

2. 2AlBr₃(aq) + 3Cl₂(g) → 2AlCl₃(aq) + 3Br₂(l)

3. 2HNO₃(aq) + Ba(OH)₂(aq) → Ba(NO₃)₂(aq) + 2H₂O(l)

4. 2Al(s) + 3Pb(NO₃)₂ → 2Al(NO₃)₃(aq) + 3Pb(s)

5. 3NaOH(aq) + Fe(NO₃)₃ → Fe(OH)₃(s) + 3NaNO₃(aq)

Explanation:

From the question given, I have been able to balance the chemical equations correctly.

In balancing chemical equations, the chemical equation must have equal number of atoms for each element that are both in the reactant side and in the product side.

For the above to be achieved, the number of atoms in each element will have to be multiplied and added.

A look at the balanced chemical equation above, you will discover that each element has the same number of atoms both in the reactant side and in the product side.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

its first and third is your answer i did the qustion the fourth isnt right