Kp/Kc for reaction for the equilibrium, A(g) ⇌ C(g)+B(g), is . (Kc is the equilibrium constant in terms of concentrations, Kp is the equilibrium constant in terms of pressures, R is the gas constant, T is the temperature)

Select one:
(RT)2
(RT)-1
(RT)-2
(RT)-1.5
RT

Kp/Kc = RT

Given

Reaction

A(g) ⇌ C(g)+B(g)

Required

Kp/Kc

Solution

For reaction :

pA + qB ⇒ mC + nD  

While the equilibrium constant Kp is based on the partial pressure  

The value of Kp and Kc can be linked to the formula '  

R = gas constant = 0.0821 L.atm / mol.K  

Δn=moles products - moles reactants or

number of product coefficients-number of reactant coefficients  

For reaction :

A(g) ⇌ C(g)+B(g)

number of product coefficients = 1+1=2

number of reactant coefficients   = 1

Δn= 2 - 1 =1

So Kp/Kc = RT

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"