A sample of oxygen occupies a volume of 150 cm3 at 72 C. What will be volume of oxygen when the temperature drops to 2 C?

V₂ = 119.59 cm³

Explanation:

Given data:

Initial volume = 150 cm³

Initial temperature = 72°C

Final volume = ?

Final temperature = 2°C

Solution:

Initial temperature = 72°C (72 +273.15 K = 345.15 K)

Final temperature = 2°C (2 + 273.15 k = 275.15 K)

Solution:

According to the Charles Law.

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 150 cm³ × 275.15 K /345.15 K

V₂ = 41272.5 cm³.K / 298 K

V₂ = 119.59 cm³

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.

2b2t

explanation:

2b2t