What is the boiling point of a solution of 0.150mole Al(No3)3 in 0.500kg water. kb= 0.512

The boiling point of a solution : 100.1536 °C

Given

0.150 mole Al(NO₃)₃ in 0.500 kg water. kb= 0.512

Required

The boiling point

Solution

Colligative properties

ΔTb = Kb . m

m = molality = mol solute per kg solvent

m = 0.15 moles : 0.5 kg

m = 0.3

ΔTb = 0.512 x 0.3

ΔTb = 0.1536

ΔTb = Tb solution - Tb solvent (solvent=water, boiling point = 100 °C)

0.1536 = Tb solution - 100

Tb solution = 100.1536 °C

the answer to your question is c.

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